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Proof step 5 from proof inv-get-inverse-succ (previous step)

stutf(nσ), ⌜n⌝ < leninv(nσ), ⌜(leninv(nσ) = ∞ ⊃ ⌜λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n⌝ ;⌜(λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to leninv(nσ).n⌝ )[n]⌝ + ⌜1⌝ < # nσ ⊦ nσ[(leninv(nσ) = ∞ ⊃ ⌜λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n⌝ ;⌜(λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to leninv(nσ).n⌝ )[n] + 1] = n + 1

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 3

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