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Proof step 58 from proof inv-get-inverse-succ (previous step)

leninv(nσ) = ⌜n0⌝ , stutf(nσ), ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜1⌝ < # nσ, n < n0 ⊦ nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + 1] = n + 1, n0 = 0

User applied rule constructor cut

And obtained the following new goals

Proof step 59:
n0 = n1 +1, leninv(nσ) = ⌜n0⌝ , stutf(nσ), ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ + ⌜1⌝ < # nσ, n < n0 ⊦ nσ[max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n + 1] = n + 1, n0 = 0

Rule argument

var: n0

Additional information

Used simplifier rules: nat freely generated by 0, +1;;