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Proof step 81 from proof inv-get-inverse-succ (previous step)

# nσ = ∞, nσ[n1] = n ∧ (∀ m. nσ[m] = n → ¬ n1 < m), stutf(nσ), n ≤ nσ[m], ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ nσ[n1 + 1] = n + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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