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Proof step 99 from proof inv-get-inverse-succ (previous step)

(∀ n0. ∃ n1. n0 < n1 ∧ ¬ m < n1 ∧ nσ[n1] = n) ∨ (∀ n0. ¬(¬ m < n0 ∧ nσ[n0] = n)), # nσ = ⌜m⌝ + ⌜1⌝ , stutf(nσ), n ≤ nσ[m], ∞.n < m ⊦ nσ[∞.n + 1] = n + 1, m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 100:
# nσ = ⌜m⌝ + ⌜1⌝ , stutf(nσ), n ≤ nσ[m], ∞.n < m, (∀ n0. ∃ n1. n0 < n1 ∧ ¬ m < n1 ∧ nσ[n1] = n) ∨ (∀ n0. m < n0 ∨ nσ[n0] ≠ n) ⊦ nσ[∞.n + 1] = n + 1, m = 0

Proof step 99 from proof inv-get-inverse-succ (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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