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Proof step 10 from proof inv-get-inverse (previous step)

# nσ = ∞, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ nσ[max∞(λ n0. nσ[n0] = n).n] = n

User applied rule cut formula

And obtained the following new goals

Proof step 11:
max∞(λ n0. nσ[n0] = n) = ∞, # nσ = ∞, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ nσ[max∞(λ n0. nσ[n0] = n).n] = n
Proof step 38:
# nσ = ∞, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ max∞(λ n0. nσ[n0] = n) = ∞, nσ[max∞(λ n0. nσ[n0] = n).n] = n

Rule argument

fma: max∞(λ n0. nσ[n0] = n) = ∞

Additional information

Used formulas: max∞(λ n0. nσ[n0] = n) = ∞