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Proof step 26 from proof inv-get-inverse (previous step)

∀ n0. nσ[n0] ≠ n, # nσ = ∞, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ nσ[∞.n] = n

User applied rule weakening

And obtained the following new goals

Proof step 27:
∀ n0. nσ[n0] ≠ n, # nσ = ∞, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦

Rule argument

poslist: right 1

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