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Proof step 31 from proof inv-get-inverse (previous step)

# nσ = ∞, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0], ¬(∀ n1. nσ[n1] ≠ n0) ∨ # nσ ≠ ∞ ∨ ¬ stutf(nσ) ∨ ¬(∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0]), ∀ n. nσ[n] ≠ n0 + 1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 32:
# nσ = ∞, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0], ∀ n1. nσ[n1] ≠ nσ[n] + 1 ⊦

Proof step 31 from proof inv-get-inverse (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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