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Proof step 40 from proof inv-get-inverse (previous step)

# nσ = ∞, max∞(λ n0. nσ[n0] = n) = ⌜n1⌝ , stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ nσ[n1] = n

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: inst: name: maxinf-fin seq: ⊦ max∞(np) = ⌜n⌝ ↔ np(n) ∧ (∀ m. np(m) → ¬ n < m) subst: [n, np] → [n1, λ n0. nσ[n0] = n] flags: rewrite, current

Additional information

Used terms: n1, λ n0. nσ[n0] = n