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Proof step 43 from proof inv-get-inverse (previous step)

stutf(nσ), ⌜n⌝ < leninv(nσ) ⊦ leninv(nσ) = ∞, nσ[((λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to leninv(nσ).n)[n]] = n

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 44:
leninv(nσ) = ⌜n0⌝ , stutf(nσ), ⌜n⌝ < leninv(nσ) ⊦ leninv(nσ) = ∞, nσ[((λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to n0)[n]] = n

Rule argument

spec: nat-inf-basic inst: name: elim seq: ⊦ n∞ ≠ ∞ → (n = n∞.n ↔ n∞ = ⌜n⌝ ) subst: [n∞, m] → [leninv(nσ), m0] flags:

Additional information

Used simplifier rules: ⊦ n∞ ≠ ∞ → (n = n∞.n ↔ n∞ = ⌜n⌝ ); (elim) Used terms: leninv(nσ), m0