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Proof step 48 from proof inv-get-inverse (previous step)

max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n) = ∞, leninv(nσ) = ⌜n0⌝ , n < n0, stutf(nσ) ⊦

User applied rule constructor cut

And obtained the following new goals

Proof step 49:
n0 = n1 +1, max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n) = ∞, leninv(nσ) = ⌜n0⌝ , n < n0, stutf(nσ) ⊦

Rule argument

var: n0

Additional information

Used simplifier rules: nat freely generated by 0, +1;;%zero-01: ⊦ ¬ m < 0; from specification nat-basic1