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Proof step 60 from proof inv-get-inverse (previous step)

# nσ = ∞, stutf(nσ), nσ[n0] ≤ nσ[m], m < n0, ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 5 terms: n0

Additional information

Used simplifier rules: a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2%eq: ⊦ m = n + 1 → ¬ m ≤ n; from specification nat Used terms: n0