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Proof step 11 from proof inv-get-lslen (previous step)

¬ max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n) ≠ ∞, leninv(nσ) = ⌜n0⌝ , stutf(nσ), n < n0 ⊦ n0 = 0, ⌜max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = n).n⌝ < # nσ

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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