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Proof step 26 from proof inv-get-lslen (previous step)

# nσ = ⌜m⌝ + ⌜1⌝ , n ≤ nσ[m], stutf(nσ), m < ∞.n, (∀ n0. ∃ n1. n0 < n1 ∧ ¬ m < n1 ∧ nσ[n1] = n) ∨ (∀ n0. m < n0 ∨ nσ[n0] ≠ n) ⊦ ∞.n = 0

User applied rule case distinction

And obtained the following new goals

Proof step 27:
∀ n0. ∃ n1. n0 < n1 ∧ ¬ m < n1 ∧ nσ[n1] = n, # nσ = ⌜m⌝ + ⌜1⌝ , n ≤ nσ[m], stutf(nσ), m < ∞.n ⊦ ∞.n = 0
Proof step 28:
∀ n0. m < n0 ∨ nσ[n0] ≠ n, # nσ = ⌜m⌝ + ⌜1⌝ , n ≤ nσ[m], stutf(nσ), m < ∞.n ⊦ ∞.n = 0

Rule argument

pos: left 5

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