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Proof step 12 from proof inv-inverts-last (previous step)

leninv(nσ) = ∞, # nσ = ⌜n⌝ + ⌜1⌝ , stutf(nσ), (∀ n0. ∃ n1. n0 < n1 ∧ ¬ n < n1 ∧ nσ[n1] = nσ[n]) ∨ (∀ n0. n < n0 ∨ nσ[n0] ≠ nσ[n]) ⊦ ∞.n = n

User applied rule case distinction

And obtained the following new goals

Proof step 13:
∀ n0. ∃ n1. n0 < n1 ∧ ¬ n < n1 ∧ nσ[n1] = nσ[n], leninv(nσ) = ∞, # nσ = ⌜n⌝ + ⌜1⌝ , stutf(nσ) ⊦ ∞.n = n
Proof step 14:
∀ n0. n < n0 ∨ nσ[n0] ≠ nσ[n], leninv(nσ) = ∞, # nσ = ⌜n⌝ + ⌜1⌝ , stutf(nσ) ⊦ ∞.n = n

Rule argument

pos: left 4

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