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Proof step 21 from proof inv-inverts-last (previous step)

nσ[n1] = nσ[n], leninv(nσ) = ∞, # nσ = ⌜n⌝ + ⌜1⌝ , n1 < n, stutf(nσ), ∀ m. ¬ n < m ∧ nσ[m] = nσ[n] → ¬ n1 < m ⊦ n1 = n

User applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: n abort: F discard: F computed: T

Additional information

Used simplifier rules: ref-1: ⊦ ¬ n < n; from specification nat-basic1 Used terms: n