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Proof step 39 from proof inv-inverts-last (previous step)

∀ n0. n < n0 ∨ nσ[n0] ≠ nσ[n], leninv(nσ) = ⌜n1⌝ , # nσ = ⌜n⌝ + ⌜1⌝ , stutf(nσ), nσ[n] < n1 ⊦ ∞.n = n

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: n

Additional information

Used simplifier rules: ref-1: ⊦ ¬ n < n; from specification nat-basic1 Used terms: n