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Proof step 5 from proof inv-inverts-last (previous step)

# nσ = ⌜n⌝ + ⌜1⌝ , stutf(nσ) ⊦ (leninv(nσ) = ∞ ⊃ ⌜λ m. max∞(λ n0. ¬ n < n0 ∧ nσ[n0] = m).n⌝ ;⌜(λ m. max∞(λ n0. ¬ n < n0 ∧ nσ[n0] = m).n) to leninv(nσ).n⌝ )[nσ[n]] = n

User applied rule case distinction

And obtained the following new goals

Proof step 6:
leninv(nσ) = ∞, # nσ = ⌜n⌝ + ⌜1⌝ , stutf(nσ) ⊦ ⌜λ m. max∞(λ n0. ¬ n < n0 ∧ nσ[n0] = m).n⌝ [nσ[n]] = n
Proof step 22:
leninv(nσ) ≠ ∞, # nσ = ⌜n⌝ + ⌜1⌝ , stutf(nσ) ⊦ ⌜(λ m. max∞(λ n0. ¬ n < n0 ∧ nσ[n0] = m).n) to leninv(nσ).n⌝ [nσ[n]] = n

Rule argument

pos: right 1

Proof step 5 from proof inv-inverts-last (previous step)

User applied rule case distinction

And obtained the following new goals

Rule argument

Additional information