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Proof step 11 from proof inv-inverts-leq (previous step)

max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]) = ∞, (∀ n0. ∃ n1. n0 < n1 ∧ ⌜n1⌝ < # nσ ∧ nσ[n1] = nσ[n]) ∨ (∀ n0. ¬ ⌜n0⌝ < # nσ ∨ nσ[n0] ≠ nσ[n]), leninv(nσ) = ∞, max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]).n < n, stutf(nσ), ⌜n⌝ < # nσ ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]) = ∞, leninv(nσ) = ∞, ∞.n < n, stutf(nσ), ⌜n⌝ < # nσ, (∀ n0. ∃ n1. n0 < n1 ∧ ⌜n1⌝ < # nσ ∧ nσ[n1] = nσ[n]) ∨ (∀ n0. ¬ ⌜n0⌝ < # nσ ∨ nσ[n0] ≠ nσ[n]) ⊦

Proof step 11 from proof inv-inverts-leq (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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