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Proof step 15 from proof inv-inverts-leq (previous step)

leninv(nσ) = ∞, ∞.n < n, stutf(nσ), ⌜n⌝ < # nσ, (∀ n0. ∃ n1. n0 < n1 ∧ ⌜n1⌝ < # nσ ∧ nσ[n1] = nσ[n]) ∨ (∀ n0. ¬ ⌜n0⌝ < # nσ ∨ nσ[n0] ≠ nσ[n]) ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 16:
∀ n0. ∃ n1. n0 < n1 ∧ ⌜n1⌝ < # nσ ∧ nσ[n1] = nσ[n], leninv(nσ) = ∞, ∞.n < n, stutf(nσ), ⌜n⌝ < # nσ ⊦
Proof step 25:
∀ n0. ¬ ⌜n0⌝ < # nσ ∨ nσ[n0] ≠ nσ[n], leninv(nσ) = ∞, ∞.n < n, stutf(nσ), ⌜n⌝ < # nσ ⊦

Rule argument

pos: left 5

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