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Proof step 33 from proof inv-inverts-leq (previous step)

leninv(nσ) = ⌜n0⌝ , nσ[n] < n0, ⌜n⌝ < # nσ, stutf(nσ), max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]).n < n ⊦

User applied rule constructor cut

And obtained the following new goals

Proof step 34:
n0 = n1 +1, leninv(nσ) = ⌜n0⌝ , nσ[n] < n0, ⌜n⌝ < # nσ, stutf(nσ), max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]).n < n ⊦

Rule argument

var: n0

Additional information

Used simplifier rules: nat freely generated by 0, +1;;%zero-01: ⊦ ¬ m < 0; from specification nat-basic1