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Proof step 39 from proof inv-inverts-leq (previous step)

# nσ = ∞, nσ[m] = n1 ∧ (∀ m0. m < m0 → nσ[m0] = nσ[m] + 1), ⌜n⌝ < # nσ, stutf(nσ), max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]).n < n, nσ[n] ≤ n1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 40:
# nσ = ∞, stutf(nσ), nσ[n] ≤ nσ[m], max∞(λ n0. nσ[n0] = nσ[n]).n < n, ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Rule argument

Additional information

Used simplifier rules: less-inf2: ⊦ ⌜m⌝ < ∞; from specification nat-inf