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Proof step 54 from proof inv-inverts-leq (previous step)

max∞(λ n0. nσ[n0] = nσ[n]) = ⌜n1⌝ ∧ max∞(λ n0. nσ[n0] = nσ[n]) ≠ ∞, # nσ = ∞, stutf(nσ), nσ[n] ≤ nσ[m], n1 < n, ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 55:
# nσ = ∞, max∞(λ n0. nσ[n0] = nσ[n]) = ⌜n1⌝ , n1 < n, nσ[n] ≤ nσ[m], stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Rule argument

Additional information

Used simplifier rules: disj: ⊦ ⌜m⌝ ≠ ∞; from specification nat-inf-basic