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Proof step 58 from proof inv-inverts-leq (previous step)

# nσ = ∞, nσ[n1] = nσ[n], n1 < n, nσ[n] ≤ nσ[m], stutf(nσ), ∀ m. nσ[m] = nσ[n] → ¬ n1 < m, ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: n

Additional information

Used terms: n