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Proof step 65 from proof inv-inverts-leq (previous step)

# nσ = ⌜m⌝ + ⌜1⌝ , max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = nσ[n]).n < m, n ≤ m, max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = nσ[n]).n ≤ m, nσ[n] ≤ nσ[m], max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = nσ[n]).n < n, stutf(nσ) ⊦ max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = nσ[n]) ≠ ∞

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 66:
max∞(λ n0. ¬ m < n0 ∧ nσ[n0] = nσ[n]) = ∞, # nσ = ⌜m⌝ + ⌜1⌝ , n ≤ m, ∞.n ≤ m, nσ[n] ≤ nσ[m], ∞.n < n, stutf(nσ), ∞.n < m ⊦

Rule argument

Additional information

Used simplifier rules: fle: ⊦ m < n ∧ n ≤ n0 → m < n0; (forward) from specification nat