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Proof step 70 from proof inv-inverts-leq (previous step)

∀ n0. ∃ n1. n0 < n1 ∧ ¬ m < n1 ∧ nσ[n1] = nσ[n], # nσ = ⌜m⌝ + ⌜1⌝ , n ≤ m, ∞.n ≤ m, nσ[n] ≤ nσ[m], ∞.n < n, stutf(nσ), ∞.n < m ⊦

User applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: m + 1 abort: F discard: T computed: F

Additional information

Used simplifier rules: nls-fst: ⊦ ¬ m < n → ¬ m + m0 < n; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: m + 1