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Proof step 71 from proof inv-inverts-leq (previous step)

∀ n0. m < n0 ∨ nσ[n0] ≠ nσ[n], # nσ = ⌜m⌝ + ⌜1⌝ , n ≤ m, ∞.n ≤ m, nσ[n] ≤ nσ[m], ∞.n < n, stutf(nσ), ∞.n < m ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: n

Additional information

Used simplifier rules: le-ls-simp: ⊦ m ≤ n → (n < m ↔ false); from specification nat Used terms: n