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Proof step 75 from proof inv-inverts-leq (previous step)

# nσ = ⌜m⌝ + ⌜1⌝ , (¬ m < n1 ∧ nσ[n1] = nσ[n]) ∧ (∀ m0. ¬ m < m0 ∧ nσ[m0] = nσ[n] → ¬ n1 < m0), n1 < m, stutf(nσ), n1 < n, nσ[n] ≤ nσ[m], n1 ≤ m, n ≤ m ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 76:
# nσ = ⌜m⌝ + ⌜1⌝ , nσ[n1] = nσ[n], n1 < m, stutf(nσ), n1 < n, nσ[n] ≤ nσ[m], n1 ≤ m, n ≤ m, ∀ m0. ¬ m < m0 ∧ nσ[m0] = nσ[n] → ¬ n1 < m0 ⊦

Rule argument

Additional information

Used simplifier rules: ls-02: ⊦ m < n → ¬ n < m; from specification nat-basic1