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Proof step 15 from proof inv-inverts (previous step)

nσ[n + 1] = nσ[n] + 1, max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]) = ⌜n⌝ , leninv(nσ) = ⌜n2⌝ + ⌜1⌝ , ⌜n⌝ + ⌜1⌝ < # nσ, stutf(nσ) ⊦ ((λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to n2 + 1)[nσ[n]] = n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ stutf(nσ) → (leninv(nσ) = ⌜n⌝ + ⌜1⌝ ↔ (# nσ = ∞ ⊃ ∃ m. nσ[m] = n ∧ (∀ m0. m < m0 → nσ[m0] = n + 1);nσ[(# nσ).n - 1] = n))
Proof step 17:
stutf(nσ), nσ[n + 1] = nσ[n] + 1, max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]) = ⌜n⌝ , (# nσ = ∞ ⊃ ∃ m. nσ[m] = n2 ∧ (∀ m0. m < m0 → nσ[m0] = n2 + 1);nσ[(# nσ).n - 1] = n2), ⌜n⌝ + ⌜1⌝ < # nσ, stutf(nσ) ⊦ ((λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to n2 + 1)[nσ[n]] = n

Rule argument

spec: inst: name: leninv-succ seq: ⊦ stutf(nσ) → ( leninv(nσ) = ⌜n⌝ + ⌜1⌝ ↔ (# nσ = ∞ ⊃ ∃ m. nσ[m] = n ∧ (∀ m0. m < m0 → nσ[m0] = n + 1) ;nσ[(# nσ).n - 1] = n )) subst: [n, nσ] → [n2, nσ] flags: rewrite, current

Additional information

Used terms: n2, nσ