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Proof step 7 from proof inv-inverts (previous step)

leninv(nσ) ≠ ∞, max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]) = ⌜n⌝ , nσ[n + 1] = nσ[n] + 1, stutf(nσ), ⌜n⌝ + ⌜1⌝ < # nσ ⊦ ⌜(λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to leninv(nσ).n⌝ [nσ[n]] = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
max∞(λ n0. ⌜n0⌝ < # nσ ∧ nσ[n0] = nσ[n]) = ⌜n⌝ , nσ[n + 1] = nσ[n] + 1, stutf(nσ), ⌜n⌝ + ⌜1⌝ < # nσ ⊦ leninv(nσ) = ∞, ((λ m. max∞(λ n. ⌜n⌝ < # nσ ∧ nσ[n] = m).n) to leninv(nσ).n)[nσ[n]] = n

Rule argument

Additional information

Used simplifier rules: sel-fin: ⊦ ⌜nl⌝ [n] = nl[n]; from specification stream[natstream]