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Proof step 23 from proof inv-ls-succ (previous step)

∀ n0. nσ[n0] ≠ n + 1, # nσ = ∞, stutf(nσ), ∞.n ≤ max∞(λ n0. nσ[n0] = n).n, ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦

User applied rule weakening

And obtained the following new goals

Proof step 24:
∀ n0. nσ[n0] ≠ n + 1, # nσ = ∞, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦

Rule argument

poslist: left 4

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