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Proof step 12 from proof leninv-inf-strong (previous step)

# nσ = ∞, stutf(nσ), m0 < nσ[m], ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ nσ[m] = 0, ∃ m. m0 + 1 < nσ[m]

User applied rule exists right

And obtained the following new goals

Proof step 13:
# nσ = ∞, stutf(nσ), m0 < nσ[m], ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0] ⊦ nσ[m] = 0, m0 + 1 < nσ[m], ∃ m. m0 + 1 < nσ[m]

Rule argument

pos: right 2 terms: m abort: F discard: F computed: F

Additional information

Used terms: m