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Proof step 16 from proof leninv-inf (previous step)

n = m2 + 1 ∧ n ≠ 0, # nσ = ∞, nσ[m0] = m2, stutf(nσ), nσ[m] + 1 < n, m0 < m1 ⊦ nσ[m1] = m2, ∃ m0. m < m0 ∧ nσ[m] < nσ[m0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%l: ⊦ m + n < m + n0 ↔ n < n0; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%oz: ⊦ m + 1 ≠ 0; from specification nat-basic2