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Proof step 19 from proof leninv-inf (previous step)

# nσ = ∞, nσ[m] < nσ[m0], stutf(nσ), m0 < m1, m0 ≤ m ⊦ nσ[m1] = nσ[m0]

User applied rule insert lemma

And obtained the following new goals

Proof step 20:
⊦ mon≤(nσ) ∧ m ≤ n ∧ ⌜n⌝ < # nσ → nσ[m] ≤ nσ[n]

Rule argument

spec: inst: name: monle-leq seq: ⊦ mon≤(nσ) ∧ m ≤ n ∧ ⌜n⌝ < # nσ → nσ[m] ≤ nσ[n] subst: [nσ, m, n] → [nσ, m0, m] flags: current, []

Additional information

Used simplifier rules: stutf-monle: ⊦ stutf(nσ) → (¬ mon≤(nσ) ↔ false);%ls-le-simp: ⊦ m < n → (n ≤ m ↔ false); from specification nat%less-inf2: ⊦ ⌜m⌝ < ∞; from specification nat-inf Used terms: nσ, m0, m