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Proof step 22 from proof leninv-inf (previous step)

∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0], # nσ = ∞, stutf(nσ) ⊦ (∀ n. ∃ n0. n < n0 ∧ (∃ m. nσ[m] = n0 - 1 ∧ ¬(∀ m0. m < m0 → nσ[m0] = n0 - 1))) ∨ (∀ n. ¬(n ≠ 0 → (∃ m. nσ[m] = n - 1 ∧ ¬(∀ m0. m < m0 → nσ[m0] = n - 1))))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
# nσ = ∞, stutf(nσ), ∀ m. ∃ m0. m < m0 ∧ nσ[m] < nσ[m0], n ≠ 0 → nσ[m] = n - 1 ∧ ¬(m < m0 → nσ[m0] = n - 1) ⊦ ∃ n1. n0 < n1 ∧ (∃ m. nσ[m] = n1 - 1 ∧ ¬(∀ m0. m < m0 → nσ[m0] = n1 - 1))

Proof step 22 from proof leninv-inf (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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