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Proof step 66 from proof leninv-inf (previous step)

# nσ = ⌜n0⌝ + ⌜1⌝ , stutf(nσ), ∀ n. ¬(n ≠ 0 → (∃ m. ¬ n0 < m ∧ nσ[m] = n - 1)) ⊦ ∃ m. ¬ n0 < m ∧ nσ[m] = nσ[n0]

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: n0

Additional information

Used simplifier rules: ref-1: ⊦ ¬ n < n; from specification nat-basic1 Used terms: n0