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Proof step 100 from proof leninv-succ (
previous step
)
# nσ = ⌜m1⌝ + ⌜1⌝ , stutf(nσ), m ≤ m1, ∀ m0. (m0 ≠ 0 → (∃ m2. ¬ m1 < m2 ∧ nσ[m2] = m0 - 1)) → ¬ nσ[m] + 1 < m0 ⊦ ∃ m0. ¬ m1 < m0 ∧ nσ[m0] = nσ[m1], nσ[m1] = nσ[m]
Heuristic quantifier closing applied rule exists right
And closed the goal!
Rule argument
pos: right 1 terms: m1
Additional information
Used simplifier rules: ref-1: ⊦ ¬ n < n; from specification nat-basic1 Used terms: m1