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Proof step 12 from proof leninv-succ (previous step)

# nσ = ∞, stutf(nσ) ⊦ (∃ m. nσ[m] = n ∧ ¬(∀ m0. m < m0 → nσ[m0] = nσ[m])) ∧ (∀ m. (m ≠ 0 → (∃ m0. nσ[m0] = m - 1 ∧ ¬(∀ m1. m0 < m1 → nσ[m1] = m - 1))) → ¬ n + 1 < m) ↔ (∃ m. nσ[m] = n ∧ (∀ m0. m < m0 → nσ[m0] = nσ[m] + 1))

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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