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Proof step 20 from proof leninv-succ (previous step)

nσ[m0] = m3 + 1, # nσ = ∞, nσ[m] ≤ m3, stutf(nσ), m < m0, (∃ m1. nσ[m1] = m3 ∧ ¬(∀ m2. m1 < m2 → nσ[m2] = nσ[m1])) → ¬ nσ[m] < m3, ∀ m0. (m0 ≠ 0 → (∃ m1. nσ[m1] = m0 - 1 ∧ ¬(∀ m2. m1 < m2 → nσ[m2] = m0 - 1))) → ¬ nσ[m] + 1 < m0 ⊦ m0 = 0, m3 + 1 = nσ[m], ∃ m0. nσ[m0] = nσ[m] ∧ (∀ m1. m0 < m1 → nσ[m1] = nσ[m0] + 1)

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: left 6

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