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Proof step 74 from proof leninv-succ (previous step)

# nσ = ∞, stutf(nσ), ∀ m0. m < m0 → nσ[m0] = nσ[m] + 1 ⊦ (∃ m0. nσ[m0] = nσ[m] ∧ ¬(∀ m1. m0 < m1 → nσ[m1] = nσ[m0])) ∧ ((m0 ≠ 0 → nσ[m1] = m0 - 1 ∧ ¬(m1 < m2 → nσ[m2] = m0 - 1)) → ¬ nσ[m] + 1 < m0)

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 1

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