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Proof step 95 from proof leninv-succ (previous step)

# nσ = ⌜m1⌝ + ⌜1⌝ , stutf(nσ) ⊦ (∃ m. ¬ m1 < m ∧ nσ[m] = n) ∧ (∀ m. (m ≠ 0 → (∃ m0. ¬ m1 < m0 ∧ nσ[m0] = m - 1)) → ¬ n + 1 < m) ↔ nσ[m1] = n

User applied rule case distinction

And obtained the following new goals

Proof step 96:
(∃ m. ¬ m1 < m ∧ nσ[m] = n) ∧ (∀ m. (m ≠ 0 → (∃ m0. ¬ m1 < m0 ∧ nσ[m0] = m - 1)) → ¬ n + 1 < m), # nσ = ⌜m1⌝ + ⌜1⌝ , stutf(nσ) ⊦ nσ[m1] = n
Proof step 103:
nσ[m1] = n, # nσ = ⌜m1⌝ + ⌜1⌝ , stutf(nσ) ⊦ (∃ m. ¬ m1 < m ∧ nσ[m] = n) ∧ (∀ m. (m ≠ 0 → (∃ m0. ¬ m1 < m0 ∧ nσ[m0] = m - 1)) → ¬ n + 1 < m)

Rule argument

pos: right 1

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