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Proof step 13 from proof leninv-zero (previous step)

# nσ = ∞, stutf(nσ), ∀ m. (∃ m0. nσ[m0] = m - 1 ∧ ¬(∀ m1. m0 < m1 → nσ[m1] = m - 1)) → m = 0 ⊦ nσ[n] = 0

User applied rule all left

And obtained the following new goals

Proof step 14:
# nσ = ∞, stutf(nσ), (∃ m0. nσ[m0] = 0 +1 - 1 ∧ ¬(∀ m1. m0 < m1 → nσ[m1] = 0 +1 - 1)) → 0 +1 = 0, ∀ m. (∃ m0. nσ[m0] = m - 1 ∧ ¬(∀ m1. m0 < m1 → nσ[m1] = m - 1)) → m = 0 ⊦ nσ[n] = 0

Rule argument

pos: left 3 terms: 0 +1 abort: F discard: F computed: T

Additional information

Used terms: 0 +1