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Proof step 17 from proof leninv-zero (
previous step
)
# nσ = ∞, stutf(nσ), ∀ m. (∃ m0. nσ[m0] = m - 1 ∧ ¬(∀ m1. m0 < m1 → nσ[m1] = m - 1)) → m = 0, ∀ m. m ≠ 0 → nσ[m] = 0 ⊦ nσ[n] = 0, ∃ m. nσ[m] = 0 ∧ ¬(∀ m0. m < m0 → nσ[m0] = 0)
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 4 terms: n
Additional information
Used simplifier rules: stutf-zero: ⊦ stutf(nσ) → nσ[0] = 0; Used terms: n