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Proof step 18 from proof leninv-zero (
previous step
)
stutf(nσ), ∀ m. (∃ m0. ⌜m0⌝ < # nσ ∧ nσ[m0] = m - 1 ∧ (# nσ ≠ ∞ ∨ ¬(∀ m1. m0 < m1 → nσ[m1] = m - 1))) → m = 0 ⊦ # nσ = ∞, # nσ = ∞ ∧ (⌜n⌝ < # nσ → nσ[n] = 0)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 19
:
stutf(nσ), ∀ m. (∃ m0. ⌜m0⌝ < # nσ ∧ nσ[m0] = m - 1) → m = 0 ⊦ # nσ = ∞
Rule argument
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