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Proof step 12 from proof leq-leninv (previous step)

stutf(nσ), (# nσ = ∞ ⊃ ∃ m. nσ[m] = n1 ∧ (∀ m0. m < m0 → nσ[m0] = n1 + 1);nσ[(# nσ).n - 1] = n1), ⌜n⌝ < # nσ, stutf(nσ), n1 + 1 < nσ[n] ⊦ nσ[n] = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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