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Proof step 2 from proof leq-leninv (previous step)

⌜n⌝ < # nσ, stutf(nσ), leninv(nσ) < ⌜nσ[n]⌝ ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ leninv(nσ) < n∞ ↔ (∃ n. leninv(nσ) = ⌜n⌝ ∧ ⌜n⌝ < n∞)
Proof step 4:
⌜n⌝ < # nσ, stutf(nσ), ∃ n0. leninv(nσ) = ⌜n0⌝ ∧ ⌜n0⌝ < ⌜nσ[n]⌝ ⊦

Rule argument

spec: inst: name: leninv-less seq: ⊦ leninv(nσ) < n∞ ↔ (∃ n. leninv(nσ) = ⌜n⌝ ∧ ⌜n⌝ < n∞) subst: [n∞, nσ] → [⌜nσ[n]⌝ , nσ] flags: rewrite, current

Additional information

Used terms: ⌜nσ[n]⌝ , nσ