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Proof step 20 from proof leq-leninv (previous step)

⌜n⌝ < # nσ, stutf(nσ), nσ[(# nσ).n - 1] + 1 < nσ[n] ⊦ nσ[n] = 0, # nσ = ∞

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 21:
# nσ = ⌜n0⌝ , ⌜n⌝ < # nσ, stutf(nσ), nσ[n0 - 1] + 1 < nσ[n] ⊦ nσ[n] = 0, # nσ = ∞

Rule argument

spec: nat-inf-basic inst: name: elim seq: ⊦ n∞ ≠ ∞ → (n = n∞.n ↔ n∞ = ⌜n⌝ ) subst: [n∞, m] → [# nσ, m] flags:

Additional information

Used simplifier rules: ⊦ n∞ ≠ ∞ → (n = n∞.n ↔ n∞ = ⌜n⌝ ); (elim) Used terms: # nσ, m