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Proof step 3 from proof less-leninv (previous step)

⌜m⌝ = leninv(nσ), # nσ = ∞, nσ[n + 1] = nσ[n] + 1, stutf(nσ) ⊦ ⌜nσ[n]⌝ < leninv(nσ)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
nσ[n + 1] = nσ[n] + 1, # nσ = ∞, ⌜m⌝ = leninv(nσ), stutf(nσ), m ≤ nσ[n] ⊦

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ m < n ↔ n ≤ m; from specification nat%less-fin: ⊦ ⌜m⌝ < ⌜n⌝ ↔ m < n; from specification nat-inf