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Proof step 9 from proof lsleninv-1 (previous step)

m0 = m1 +1, ⌜m0⌝ = leninv(nσ), stutf(nσ), ⌜m⌝ < # nσ, n < nσ[m], m0 ≤ n, m0 < nσ[m] ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
⌜m1⌝ + ⌜1⌝ = leninv(nσ), m1 < nσ[m], m1 < n, n < nσ[m], ⌜m⌝ < # nσ, stutf(nσ), m1 + 1 < nσ[m] ⊦

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; from specification nat-basic1%trans-1: ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward) from specification nat-basic1%lf: ⊦ m < n ∧ n < n0 → m +1 < n0; (forward) from specification nat-basic1%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1%succ-01: ⊦ m + 1 ≤ n ↔ m < n; from specification nat%c: ⊦ m + n = n + m; from specification nat-basic2%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%add-fin: ⊦ ⌜m + n⌝ = ⌜m⌝ + ⌜n⌝ ; from specification nat-inf%succ: ⊦ m +1 = m + 1; from specification nat-basic2