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Proof step 1 from proof lsleninv-3 (conclusion)

⊦ n < nσ[m] ∧ # nσ = # nσ0 ∧ # nσ0 = ⌜m⌝ + ⌜1⌝ ∧ stutf(nσ) → (¬ ⌜n⌝ < leninv(nσ) ↔ false)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
# nσ = # nσ0, # nσ0 = ⌜m⌝ + ⌜1⌝ , n < nσ[m], stutf(nσ) ⊦ nσ[m] = 0, ⌜n⌝ < leninv(nσ)

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic1