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Proof step 7 from proof maxinf-fin (previous step)

∀ n. ∃ n0. n < n0 ∧ np(n0), max∞(np) = ∞, np(n), ∀ m. np(m) → ¬ n < m ⊦

User applied rule all left

And obtained the following new goals

Proof step 8:
∃ n0. n < n0 ∧ np(n0), ∀ n. ∃ n0. n < n0 ∧ np(n0), max∞(np) = ∞, np(n), ∀ m. np(m) → ¬ n < m ⊦

Rule argument

pos: left 1 terms: n abort: F discard: F computed: T

Additional information

Used terms: n